2 100 -4
1.6152 No solution!
#include<stdio.h>
#include<math.h>
double f(double x){
return 8*x*x*x*x+7*x*x*x+2*x*x+3*x+6;
}
double binary_search(double x,double y,double n){
double mid=(x+y)/2;
if(y-x<=1e-7) return x; //刚开始写成 if(fabs(n-f(mid))<=1e-7) return mid; 结果超时,原来还是没理解透二分查找的具体退出边界条件!!!
else if(f(mid)>=n) return binary_search(x,mid+1e-20,n); //错了n遍,写成了mid+1e-7!!!
else return binary_search(mid+1e-20,y,n);
}
int main(){
int T;
scanf("%d",&T);
while(T--){
double y,t;
scanf("%lf",&y);
if(y<f(0)||y>f(100)){
printf("No solution!\n");
continue;
}
t=binary_search(0,100,y);
printf("%.4lf\n",t);
}
return 0;
}HDOJ-2199-Can you solve this equation?(二分查找)
原文:http://blog.csdn.net/qq_18062811/article/details/44949041