2 100 -4
1.6152 No solution!
#include<stdio.h> #include<math.h> double f(double x){ return 8*x*x*x*x+7*x*x*x+2*x*x+3*x+6; } double binary_search(double x,double y,double n){ double mid=(x+y)/2; if(y-x<=1e-7) return x; //刚开始写成 if(fabs(n-f(mid))<=1e-7) return mid; 结果超时,原来还是没理解透二分查找的具体退出边界条件!!! else if(f(mid)>=n) return binary_search(x,mid+1e-20,n); //错了n遍,写成了mid+1e-7!!! else return binary_search(mid+1e-20,y,n); } int main(){ int T; scanf("%d",&T); while(T--){ double y,t; scanf("%lf",&y); if(y<f(0)||y>f(100)){ printf("No solution!\n"); continue; } t=binary_search(0,100,y); printf("%.4lf\n",t); } return 0; }
HDOJ-2199-Can you solve this equation?(二分查找)
原文:http://blog.csdn.net/qq_18062811/article/details/44949041