Oracle把成绩行的方式转成列

1、表格中有如下数据

2、建测试数据

CREATE TABLE GRADE_TABLE(
   STU_NAME VARCHAR(20),
   SUBJECT VARCHAR(20),
   MONTH1 INT DEFAULT 0, --一月
   MONTH2 INT DEFAULT 0,--二月
   MONTH3 INT DEFAULT 0
);
insert into GRADE_TABLE(STU_NAME,SUBJECT,MONTH1,MONTH2,MONTH3) values('张三','语文','30','40','50');
insert into GRADE_TABLE(STU_NAME,SUBJECT,MONTH1,MONTH2,MONTH3) values('张三','数学','56','65','78');
insert into GRADE_TABLE(STU_NAME,SUBJECT,MONTH1,MONTH2,MONTH3) values('张三','英语','28','86','48');
insert into GRADE_TABLE(STU_NAME,SUBJECT,MONTH1,MONTH2,MONTH3) values('李四','语文','31','41','51');
insert into GRADE_TABLE(STU_NAME,SUBJECT,MONTH1,MONTH2,MONTH3) values('李四','数学','57','66','79');
insert into GRADE_TABLE(STU_NAME,SUBJECT,MONTH1,MONTH2,MONTH3) values('李四','英语','29','87','49');

3、处理SQL

select stu_name,sum(一月语文 ) 一月语文 ,sum(二月语文 ) 二月语文,sum(三月语文 ) 三月语文
,sum(一月数学 ) 一月数学 ,sum(二月数学 ) 二月数学,sum(三月数学 ) 三月数学
,sum(一月英语 ) 一月英语 ,sum(二月英语 ) 二月英语,sum(三月英语 ) 三月英语
from(
select stu_name,sum(case subject when '语文' then month1 end) as 一月语文 
,sum(case subject when '语文' then month2 end) as 二月语文 
,sum(case subject when '语文' then month3 end) as 三月语文 
,sum(case subject when '数学' then month1 end) as 一月数学 
,sum(case subject when '数学' then month2 end) as 二月数学 
,sum(case subject when '数学' then month3 end) as 三月数学 
,sum(case subject when '英语' then month1 end) as 一月英语
,sum(case subject when '英语' then month2 end) as 二月英语 
,sum(case subject when '英语' then month3 end) as 三月英语
from GRADE_TABLE 
group by stu_name,subject
) group by stu_name  --danielinbiti

Oracle把成绩行的方式转成列

原文：http://blog.csdn.net/danielinbiti/article/details/44977749