注意点:小心最后有一串空格的样例
class Solution {
public:
int lengthOfLastWord(const char *s) {
int length = 0;
int i = strlen(s) - 1;
while (i>=0 &&s[i] == ‘ ‘)
i--;
while(i>= 0&&s[i]!=‘ ‘)
{
i--; length++;
}
return length;
}
};
原文:http://www.cnblogs.com/flyjameschen/p/12e4a03d482b6982c73a1c2b362128ee.html