Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
solution:代码很简单，但是考虑的情况要很详细。
public class Solution { public int lengthOfLastWord(String s) { if(s.length()==0||s==null||s==" "){ return 0; } int n=s.length(); while(n>1&&s.charAt(n-1)==‘ ‘){ n--; } int count=0; while(n>0){ n--; if(s.charAt(n)!=‘ ‘){ count++; }else{ break; } } return count; } }
原文：http://www.cnblogs.com/joannacode/p/4418979.html