首页 > 其他 > 详细

LeetCode: Container With Most Water

时间:2015-04-12 11:54:15      阅读:218      评论:0      收藏:0      [点我收藏+]

Title :

 Given n non-negative integers a1a2, ..., an, where each represents a point at coordinate (iai). n vertical lines are drawn such that the two endpoints of line i is at (iai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

 

思路:开始题目读错了,需要考虑X轴的长度。

采用贪心的策略,从左右两边向中间靠近,每次从最短的那个“篱笆”那边向中间靠拢

class Solution{
public:
    int maxArea(vector<int> & height){
        int maxA = 0;
        int i = 0;
        int j = height.size() - 1;
        while (i < j){
            int a = (j - i) * min(height[i],height[j]);
            maxA = (a > maxA)? a : maxA;

            if (height[i] < height[j]){
                i++;
            }else{
                j--;
            }
                        //maxA = (j - i) * abs(height[i] - height[j]);
        }
        return maxA;
    }
};

 

LeetCode: Container With Most Water

原文:http://www.cnblogs.com/yxzfscg/p/4419151.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!