ZOJ 3866 Cylinder Candy

Cylinder Candy

Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge

Edward the confectioner is making a new batch of chocolate covered candy. Each candy center is shaped as a cylinder with radius r mm and height h mm.

The candy center needs to be covered with a uniform coat of chocolate. The uniform coat of chocolate is d mm thick.

You are asked to calcualte the volume and the surface of the chocolate covered candy.

Input

There are multiple test cases. The first line of input contains an integer T(1≤ T≤ 1000) indicating the number of test cases. For each test case:

There are three integers r, h, d in one line. (1≤ r, h, d ≤ 100)

Output

For each case, print the volume and surface area of the candy in one line. The relative error should be less than 10^-8.

Sample Input

2
1 1 1
1 3 5

Sample Output

32.907950527415 51.155135338077
1141.046818749128 532.235830206285

Author: ZHOU, Yuchen
Source: The 15th Zhejiang University Programming Contest

解题：Q神给的代码。。我不会积分啊，妈蛋

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 const double PI = acos(-1.0);
 4 int main(){
 5     int T;
 6     scanf("%d",&T);
 7     while(T--){
 8         double r,h,d;
 9         scanf("%lf%lf%lf",&r,&h,&d);
10         double s = 2*d*r*PI*PI + 2*(r*r+r*h+d*h+2*d*d)*PI;
11         double v = ((6*d*(d*d+r*r)-2*d*d*d)*PI + 3*r*d*d*PI*PI)/3 + (r+d)*(r+d)*h*PI;
12         printf("%.10f %.10f\n",v,s);
13     }
14     return 0;
15 }

View Code

ZOJ 3866 Cylinder Candy

原文：http://www.cnblogs.com/crackpotisback/p/4420266.html