首页 > 其他 > 详细

[LeetCode]Employees Earning More Than Their Managers,解题报告

时间:2015-04-13 20:57:40      阅读:188      评论:0      收藏:0      [点我收藏+]

目录


题目

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.

Id Name Salary ManagerId
1 Joe 70000 3
2 Henry 80000 4
3 Sam 60000 NULL
4 Max 90000 NULL

Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.

Employee
Joe

思路

题目是要从Employee表中找到员工的工资大于自己manager工资的员工姓名。

实现方案也是MYSQL的内联,直接上AC SQL。


AC SQL

select e1.Name from Employee as e1 inner join Employee as e2 
on e1.ManagerId = e2.Id and e1.Salary > e2.Salary;

[LeetCode]Employees Earning More Than Their Managers,解题报告

原文:http://blog.csdn.net/wzy_1988/article/details/45030839

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!