Remove Duplicates from Sorted Array

题目链接https://leetcode.com/problems/remove-duplicates-from-sorted-array/

思路就是维护两个pointer，一个，i， 用于遍历整个数组，另一个，len， 用于保存当前的无重复元素的数组的最后一个position

if A[i] == A[len], A[i]重复，跳过，i++;

if A[i] != A[len], 把A[i]放到A[len+1]，A[len + 1] = A[i], i++, len++;

class Solution {
public:
    int removeDuplicates(int A[], int n) {
        if(n == 0) return 0;
        int len = 0;
        for(int i = 1; i < n; i++) {
            if(A[i] != A[len]) {
                len++;
                A[len] = A[i];
            }
        }
        return len + 1;
    }
};

Reference:

　　http://bangbingsyb.blogspot.com/2014/11/leetcode-remove-duplicates-from-sorted.html

Remove Duplicates from Sorted Array

原文：http://www.cnblogs.com/walcottking/p/4430823.html