POJ 题目2083 Fractal（分治）

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Fractal

Time Limit: 1000MS		Memory Limit: 30000K
Total Submissions: 7937		Accepted: 3807

Description

A fractal is an object or quantity that displays self-similarity, in a somewhat technical sense, on all scales. The object need not exhibit exactly the same structure at all scales, but the same "type" of structures must appear on all scales.
A box fractal is defined as below :

A box fractal of degree 1 is simply
X
A box fractal of degree 2 is
X X
X
X X
If using B(n - 1) to represent the box fractal of degree n - 1, then a box fractal of degree n is defined recursively as following
```
B(n - 1)        B(n - 1)

        B(n - 1)

B(n - 1)        B(n - 1)
```

Your task is to draw a box fractal of degree n.

Input

The input consists of several test cases. Each line of the input contains a positive integer n which is no greater than 7. The last line of input is a negative integer ?1 indicating the end of input.

Output

For each test case, output the box fractal using the ‘X‘ notation. Please notice that ‘X‘ is an uppercase letter. Print a line with only a single dash after each test case.

Sample Input

Sample Output

X
-
X X
 X
X X
-
X X   X X
 X     X
X X   X X
   X X
    X
   X X
X X   X X
 X     X
X X   X X
-
X X   X X         X X   X X
 X     X           X     X
X X   X X         X X   X X
   X X               X X
    X                 X
   X X               X X
X X   X X         X X   X X
 X     X           X     X
X X   X X         X X   X X
         X X   X X
          X     X
         X X   X X
            X X
             X
            X X
         X X   X X
          X     X
         X X   X X
X X   X X         X X   X X
 X     X           X     X
X X   X X         X X   X X
   X X               X X
    X                 X
   X X               X X
X X   X X         X X   X X
 X     X           X     X
X X   X X         X X   X X
-

Source

Shanghai 2004 Preliminary

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ac代码

#include<stdio.h>
#include<string.h>
#include<math.h>
char map[1010][1010];
void dfs(int n,int x,int y)
{
	if(n==1)
	{
		map[x][y]='X';
		return;
	}
	int size=pow(3.0,n-2);
	dfs(n-1,x,y);
	dfs(n-1,x,y+2*size);
	dfs(n-1,x+size,y+size);
	dfs(n-1,x+size*2,y);
	dfs(n-1,x+size*2,y+size*2);
}
int main()
{
	int n;
	while(scanf("%d",&n)!=EOF,n!=-1)
	{
		int size=pow(3.0,n-1),i,j;
		for(i=1;i<=size;i++)
		{
			for(j=1;j<=size;j++)
			{
				map[i][j]=' ';
			}
			map[i][j+1]='\0';
		}
		dfs(n,1,1);
		for(i=1;i<=size;i++)
			printf("%s\n",map[i]+1);
		printf("-\n");
	}
}

POJ 题目2083 Fractal（分治）

原文：http://blog.csdn.net/yu_ch_sh/article/details/45098809

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