143. Reorder List

Given a singly linked list L: L0→L1→…→Ln-1→Ln,
reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→…

You must do this in-place without altering the nodes‘ values.

For example,
Given {1,2,3,4}, reorder it to {1,4,2,3}.

先找到终点，将后半段反转，然后merge前半段和后半段。

public class ReorderList {

    public void reorderList(ListNode head) {

        if (head == null) {

            return;

        }

        ListNode mid = findMid(head);

        ListNode head1 = head;

        ListNode head2 = reverseIterative(mid.next);

        mid.next = null;

        head = merge(head1, head2).next;

    }

    private ListNode merge(ListNode head1, ListNode head2) {

        ListNode head = new ListNode(0);

        head.next = head1;

        while(head1 != null && head2 != null) {

            ListNode next1 = head1.next;

            ListNode next2 = head2.next;

            head1.next = head2;

            head2.next = next1;

            head1 = next1;

            head2 = next2;

        }

        return head.next;

    }

    private ListNode findMid(ListNode head) {

        ListNode slow = head;

        ListNode fast = head;

        while(fast != null && fast.next != null) {

            slow = slow.next;

            fast = fast.next.next;

        }

        return slow;

    }

    private ListNode reverseIterative(ListNode head) {

        ListNode pre = null;

        while (head != null) {

            ListNode tmp = head.next;

            head.next = pre;

            pre = head;

            head = tmp;

        }

        return pre;

    }

}

143. Reorder List

原文：http://www.cnblogs.com/shini/p/4436575.html