Remove all elements from a linked list of integers that have value val.
Example
Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6
Return: 1 --> 2 --> 3 --> 4 --> 5
很简单吧，没什么好说的。直接上AC代码：
ListNode* removeElements(ListNode* head, int val) { if(!head) return NULL; ListNode* h=head; while(h->val==val) { if(h->next==NULL) return NULL; h = h->next; } ListNode* tmp1=h; ListNode* tmp2=h->next; while(tmp2) { if(tmp2->val == val) { tmp2= tmp2->next; tmp1->next = tmp2; } else { tmp1=tmp1->next; tmp2=tmp2->next; } } return h; }
LeetCode【203】Remove Linked List Elements
原文：http://www.cnblogs.com/ww-jin/p/4450370.html