| 标题： | Bitwise AND of Numbers Range |
| 通过率： | 25.7% |
| 难度： | 中等 |
Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive.
For example, given the range [5, 7], you should return 4.
就是将区间内的所有数字按位与的结果，如果按照每个数字的去与，那么是超时的，直接贴出代码把。。这个只能生办硬套：
1 class Solution: 2 # @param m, an integer 3 # @param n, an integer 4 # @return an integer 5 def rangeBitwiseAnd(self, m, n): 6 offset=0 7 while m !=n : 8 m>>=1 9 n>>=1 10 offset+=1 11 return m<<offset
leetcode------Bitwise AND of Numbers Range
原文：http://www.cnblogs.com/pkuYang/p/4451050.html