1 B5 = crypto:block_encrypt(des_cbc, "12345678", <<0:64>>, "87654321"). 2 %<<56,84,48,40,155,117,148,36>> 3 crypto:block_decrypt(des_cbc, "12345678", <<0:64>>, B5). 4 %<<"87654321">>
erlang des cbc
原文：http://www.cnblogs.com/weibaer/p/4456775.html
