首页 > 其他 > 详细

Leetcode#205Isomorphic Strings

时间:2015-04-29 15:17:32      阅读:173      评论:0      收藏:0      [点我收藏+]

Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given "egg""add", return true.

Given "foo""bar", return false.

Given "paper""title", return true.

题目分析,两个字符串之间的一一映射关系,采用hash来处理,因为由两个字符串构成,因此必须构建两个hash映射表,保证两个字符串中字符之间的一一对应关系

public class Solution {

    public boolean isIsomorphic(String s, String t) {

        HashMap<Character,Character> map1=new HashMap<Character, Character>();  

        HashMap<Character,Character> map2=new HashMap<Character, Character>();  

        

        

        for(int i=0;i<s.length();i++)

        {

        

            if(map1.get(s.charAt(i))==null)

                map1.put(s.charAt(i),t.charAt(i));

            if(map2.get(t.charAt(i))==null)

                map2.put(t.charAt(i),s.charAt(i));    

            if(map1.get(s.charAt(i))!=t.charAt(i)||map2.get(t.charAt(i))!=s.charAt(i))

                    return false;

        }

        return true;

    }

}


Leetcode#205Isomorphic Strings

原文:http://7061299.blog.51cto.com/7051299/1640264

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!