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11. Container With Most Water

时间:2015-04-30 07:33:02      阅读:158      评论:0      收藏:0      [点我收藏+]

Given n non-negative integers a1a2, ..., an, where each represents a point at coordinate (iai). n vertical lines are drawn such that the two endpoints of line i is at (iai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.

两个指针代表作有边界,向中间收缩。

每次收缩短的一边,因为短的一边是limit,永远不可能会是更大。

public class Solution {
  public int maxArea(int[] height) {
    int largest = 0;
    for (int i = 0, j = height.length - 1; i < j;) {
      int area = (j - i) * Math.min(height[i], height[j]);
      if (area > largest) {
        largest = area;
      }
      if (height[i] > height[j]) {
        j --;
      } else {
        i ++;
      }
    }
    return largest;
  }
}

11. Container With Most Water

原文:http://www.cnblogs.com/shini/p/4467921.html

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