|
观察下面的现象,某个数字的立方，按位累加仍然等于自身。 1^3 = 1 8^3 = 512 5+1+2=8 17^3 = 4913 4+9+1+3=17 ... 请你计算包括1,8,17在内，符合这个性质的正整数一共有多少个？ |
public class Main {
static long N, M;
static long[] num = null;
public static void main(String[] args) {
long count = 0;
for (long n = 1; n < 10000; n++) {
long tot = n * n * n;
long cmp = 0;
long t = tot;
while (t != 0) {
cmp += t % 10;
t /= 10;
}
if (cmp == n) {
count++;
System.out.println(n);
}
}
System.out.println("countwer:" + count);
}
}原文：http://blog.csdn.net/wenzhilanyu2012/article/details/45403269