【项目3-分数类中的运算符重载】
(1)实现分数类中的运算符重载,在分数类中可以完成分数的加减乘除(运算后再化简)、比较(6种关系)的运算。可以在第4周分数类代码的基础上开始工作。
/*
*Copyright (c)2014,烟台大学计算机与控制工程学院
*All rights reserved.
*dood luck
*文件名称:d.cpp
*作 者:张旺华
*完成日期:2015年5月7日
*版 本 号:v1.0
*
*/
#include <iostream>
using namespace std;
class CFraction
{
private:
int nume; // 分子
int deno; // 分母
public:
//构造函数及运算符重载的函数声明
CFraction(int n=1,int d=1);
void setCFraction(int n,int d);
void display();
friend CFraction change(CFraction &c);
CFraction operator+(CFraction &c);
CFraction operator-(CFraction &c);
CFraction operator*(CFraction &c);
CFraction operator/(CFraction &c);
bool operator > (CFraction &t);
bool operator < (CFraction &t);
bool operator >= (CFraction &t);
bool operator <= (CFraction &t);
bool operator == (CFraction &t);
bool operator != (CFraction &t);
//赋值运算符的重载
CFraction operator+=(CFraction &c);
CFraction operator-=(CFraction &c);
CFraction operator*=(CFraction &c);
CFraction operator/=(CFraction &c);
};
int gcd(int a,int b)
{
return a%b==0?b:gcd(b,a%b);
}
CFraction::CFraction(int n,int d)
{
nume=n;
deno=d;
}
void CFraction::setCFraction(int n,int d)
{
nume=n;
deno=d;
}
CFraction change(CFraction &c)
{
int t,a,b;
a=c.nume;
b=c.deno;
t=gcd(a,b);
c.nume/=t;
c.deno/=t;
return c;
}
void CFraction::display()
{
if(nume!=0&&deno!=0)
cout<<nume<<"/"<<deno<<endl;
else if(nume==0&&deno!=0)
cout<<"0"<<endl;
else
cout<<"error"<<endl;
}
CFraction CFraction::operator+(CFraction &c)
{
CFraction p;
p.nume=nume*c.deno+deno*c.nume;
p.deno=deno*c.deno;
return change(p);
}
CFraction CFraction::operator-(CFraction &c)
{
CFraction p;
p.nume=nume*c.deno-deno*c.nume;
p.deno=deno*c.deno;
return change(p);
}
CFraction CFraction::operator*(CFraction &c)
{
CFraction p;
p.nume=nume*c.nume;
p.deno=deno*c.deno;
return change(p);
}
CFraction CFraction::operator/(CFraction &c)
{
CFraction p;
p.nume=nume*c.deno;
p.deno=deno*c.nume;
return change(p);
}
bool CFraction::operator > (CFraction &t)
{
return (nume*t.deno>t.nume*deno);
}
bool CFraction::operator < (CFraction &t)
{
return (nume*t.deno<t.nume*deno);
}
bool CFraction::operator >= (CFraction &t)
{
return !(nume*t.deno<t.nume*deno);
}
bool CFraction::operator <= (CFraction &t)
{
return !(nume*t.deno>t.nume*deno);
}
bool CFraction::operator == (CFraction &t)
{
return !(nume*t.deno>t.nume*deno||nume*t.deno<t.nume*deno);
}
bool CFraction::operator != (CFraction &t)
{
return (nume*t.deno>t.nume*deno||nume*t.deno<t.nume*deno);
}
//赋值运算符的重载
CFraction CFraction::operator+=(CFraction &c)
{
nume=nume*c.deno+deno*c.nume;
deno=deno*c.deno;
return change(*this);
}
CFraction CFraction::operator-=(CFraction &c)
{
nume=nume*c.deno-deno*c.nume;
deno=deno*c.deno;
return change(*this);
}
CFraction CFraction::operator*=(CFraction &c)
{
nume=nume*c.nume;
deno=deno*c.deno;
return change(*this);
}
CFraction CFraction::operator/=(CFraction &c)
{
nume=nume*c.deno;
deno=deno*c.nume;
return change(*this);
}
int main()
{
CFraction t1(7,9),t2(11,9),t;
cout<<"t1为:";
t1.display();
cout<<"t2为:";
t2.display();
cout<<"下面比较两个时间大小:\n";
if (t1>t2) cout<<"t1>t2"<<endl;
if (t1<t2) cout<<"t1<t2"<<endl;
if (t1==t2) cout<<"t1=t2"<<endl;
if (t1!=t2) cout<<"t1≠t2"<<endl;
if (t1>=t2) cout<<"t1≥t2"<<endl;
if (t1<=t2) cout<<"t1≤t2"<<endl;
t=t1+t2;
t.display();
t=t1-t2;
t.display();
t=t1*t2;
t.display();
t=t1/t2;
t.display();
t1+=t2;
t1.display();
t1-=t2;
t1.display();
t1*=t2;
t1.display();
t1/=t2;
t1.display();
return 0;
}
学习心得:正在追赶中,好好加油,但不要图块。
原文:http://blog.csdn.net/wh201458501106/article/details/45567399