Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 19824 Accepted Submission(s):
8449
#include<stdio.h>
#include<algorithm>
using namespace std;
int set[110];
struct record
{
int beg;
int end;
int money;
}s[11000];
int find(int fa)
{
int ch=fa;
int t;
while(fa!=set[fa])
fa=set[fa];
while(ch!=fa)
{
t=set[ch];
set[ch]=fa;
ch=t;
}
return fa;
}
void mix(int x,int y)
{
int fx,fy;
fx=find(x);
fy=find(y);
if(fx!=fy)
set[fx]=fy;
}
bool cmp(record a,record b)
{
return a.money<b.money;
}
int main()
{
int city,road,n,m,j,i,sum;
while(scanf("%d",&road)&&road!=0)
{
scanf("%d",&city);
for(i=0;i<road;i++)
{
scanf("%d%d%d",&s[i].beg,&s[i].end,&s[i].money);
}
for(i=1;i<=city;i++)
set[i]=i;
sort(s,s+road,cmp);
sum=0;
for(i=0;i<road;i++)
{
if(find(s[i].beg)!=find(s[i].end))
{
mix(s[i].beg,s[i].end);
sum+=s[i].money;
}
}
j=0;
for(i=1;i<=city;i++)
{
if(set[i]==i)
j++;
if(j>1)
break;
}
if(j>1)
printf("?\n");
else
printf("%d\n",sum);
}
return 0;
}
prime算法
#include<stdio.h>
#include<string.h>
#define INF 0x3f3f3f
int lowcost[110],map[110][110],visit[110];
int city;
void prime()
{
int min,i,j,next,mincost=0;
memset(visit,0,sizeof(visit));
for(i=1;i<=city;i++)
{
lowcost[i]=map[1][i];
}
visit[1]=1;
for(i=1;i<city;i++)
{
min=INF;
for(j=1;j<=city;j++)
{
if(!visit[j]&&min>lowcost[j])
{
min=lowcost[j];
next=j;
}
}
if(min==INF)
{
printf("?\n");
return ;
}
mincost+=min;
visit[next]=1;
for(j=1;j<=city;j++)
{
if(!visit[j]&&lowcost[j]>map[next][j])
{
lowcost[j]=map[next][j];
}
}
}
printf("%d\n",mincost);
}
int main()
{
int road;
int j,i,x,y,c;
while(scanf("%d%d",&road,&city)&&road!=0)
{
memset(map,INF,sizeof(map));
while(road--)
{
scanf("%d%d%d",&x,&y,&c);
map[x][y]=map[y][x]=c;
}
prime();
}
return 0;
}
原文:http://www.cnblogs.com/tonghao/p/4487383.html