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Java for LeetCode 072 Edit Distance

时间:2015-05-17 10:36:42      阅读:325      评论:0      收藏:0      [点我收藏+]

Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.)

You have the following 3 operations permitted on a word:

a) Insert a character
b) Delete a character
c) Replace a character

解题思路:

DP问题,JAVA实现如下:

    public int minDistance(String word1, String word2) {
		int[] dp = new int[word2.length() + 1];
		for (int i = 0; i < dp.length; i++)
			dp[i] = i;
		for (int i = 1; i <= word1.length(); i++) {
			int upleft = dp[0];
			dp[0] = i;
			for (int j = 1; j <= word2.length(); j++) {
				int temp = dp[j];
				if (word1.charAt(i - 1) == word2.charAt(j - 1))
					dp[j] = upleft;
				else
					dp[j] = Math.min(upleft, Math.min(dp[j], dp[j - 1])) + 1;
				upleft = temp;
			}
		}
		return dp[word2.length()];
    }

 

Java for LeetCode 072 Edit Distance

原文:http://www.cnblogs.com/tonyluis/p/4509175.html

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