首页 > 其他 > 详细

LeeCode 判断两个二叉树是否相等

时间:2015-05-19 22:44:44      阅读:306      评论:0      收藏:0      [点我收藏+]


题目:

Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

C代码:

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     struct TreeNode *left;
 *     struct TreeNode *right;
 * };
 */
bool isSameTree(struct TreeNode* p, struct TreeNode* q) {
     if(p==NULL && q==NULL) return true;
     else if(p==NULL || q==NULL) return false;
     else return p->val==q->val && isSameTree(p->left,q->left) && isSameTree(p->right,q->right);
        
}


LeeCode 判断两个二叉树是否相等

原文:http://blog.csdn.net/xiaoshuoladashou/article/details/45849637

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!