1 题目
Given an array with n objects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note:
You are not suppose to use the library‘s sort function for this problem.
2 思路
好吧，这题是我见过最简单的，居然是中等难度，只要之前听说过这种类型的题目，都会做。就是count sort法。
数1，2，0的个数，然后再遍历赋值就行了。
3 代码
public void sortColors(int[] nums) { int redNumber = 0; int whiteNumber = 0; for(int i = 0;i < nums.length; i++){ if(nums[i] == 0){ redNumber++; }else if(nums[i]==1){ whiteNumber++; } } for(int i = 0; i < redNumber; i++){ nums[i] = 0; } for(int i = redNumber; i < redNumber + whiteNumber; i++){ nums[i] = 1; } for(int i = redNumber + whiteNumber; i < nums.length; i++){ nums[i] = 2; } }
遍历一遍的方法：https://leetcode.com/discuss/17000/share-my-one-pass-constant-space-10-line-solution
the idea is to sweep all 0s to the left and all 2s to the right, then all 1s are left in the middle.
class Solution { public: void sortColors(int A[], int n) { int second=n-1, zero=0; for (int i=0; i<=second; i++) { while (A[i]==2 && i<second) swap(A[i], A[second--]); while (A[i]==0 && i>zero) swap(A[i], A[zero++]); } } };
原文：http://www.cnblogs.com/lingtingvfengsheng/p/4518539.html