简单的四则运算计算器

<span style="font-size:24px;">#include<stdio.h>
void print_menu()
{
	printf("*********************\n");
	printf("***1.add     2.sub***\n");
	printf("***3.mul     4.div***\n");
	printf("*********************\n");
}
int add(int x,int y)
{
	return x+y;
}
int sub(int x,int y)
{
	return x-y;
}
int mul(int x,int y)
{
	return x*y;
}
int div(int x,int y)
{
	return x/y;
}

int main()
{
	int m,n;
	int input=1;
	while(input)
	{
		print_menu();
		printf("请选择>");
		scanf("%d",&input);
		printf("请输入俩个操作数：");
		scanf("%d %d",&m,&n);
		switch(input)
		{
		case 1:
			printf("%d\n",add(m,n));
			break;
		case 2:
			printf("%d\n",sub(m,n));
			break;
		case 3:
			printf("%d\n",mul(m,n));
			break;
		case 4:
			printf("%d\n",div(m,n));
			break;
		default:
			return 0;
			break;
		}
	}</span>

简单的四则运算计算器

原文：http://blog.csdn.net/kkmdmcgxi/article/details/45923239