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LeetCode: 53 Maximum Subarray

时间:2015-05-27 08:34:40      阅读:214      评论:0      收藏:0      [点我收藏+]

Find the contiguous subarray within an array (containing at least one number) which has the largest sum.

For example, given the array [−2,1,−3,4,−1,2,1,−5,4],
the contiguous subarray [4,−1,2,1] has the largest sum = 6.

 1 public class Solution{
 2     public int maxSubArray(int[] nums){
 3         int max = nums[0];
 4         int[] sum = new int[nums.length];
 5         sum[0]=nums[0];
 6 
 7         for(int i = 1; i < nums.length; i++){
 8             sum[i]=Math.max(nums[i], sum[i-1]+nums[i]);
 9             max = Math.max(sum[i], max);
10         }
11 
12         return max;
13     }
14 }

 

LeetCode: 53 Maximum Subarray

原文:http://www.cnblogs.com/hewx/p/4532422.html

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