LeetCode 215:Kth Largest Element in an Array

Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element.

For example,
Given [3,2,1,5,6,4] and k = 2, return 5.

Note: 
You may assume k is always valid, 1 ≤ k ≤ array‘s length.

Credits:
Special thanks to @mithmatt for adding this problem and creating all test cases.

代码如下：

class Solution {
public:
    int findKthLargest(vector<int>& nums, int k) {
        int length = nums.size();
        if (length == 1) {
            return nums[0];
        }
        vector<int> left;
        vector<int> right;
        
        for (int index=1; index<length; index++) {
            if (nums[index] > nums[0]) {
                right.push_back(nums[index]);
            }else{
                left.push_back(nums[index]);
            }
        }
        length = right.size();
        if (length >=k) {
            return findKthLargest(right, k);
        }else if(length == k-1){
            return nums[0];
        }else{
            return findKthLargest(left, k-length-1);
        }
    }
};

class Solution {
public:
    int findKthLargest(vector<int>& nums, int k) {
        sort(nums.begin(), nums.end());
        reverse(nums.begin(), nums.end());
        return nums[k-1];
    }
};

LeetCode 215:Kth Largest Element in an Array

原文：http://blog.csdn.net/sunao2002002/article/details/46039269