题目
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
分析这题按题目意思一步一步做就是了,属于不需要分析的动态规划了,如果可以修改grid内元素,是不需要额外空间的。
代码
public class MinimumPathSum {
public int minPathSum(int[][] grid) {
int M = grid.length;
int N = grid[0].length;
for (int j = 1; j < N; ++j) {
grid[0][j] += grid[0][j - 1];
}
for (int i = 1; i < M; ++i) {
grid[i][0] += grid[i - 1][0];
}
for (int i = 1; i < M; ++i) {
for (int j = 1; j < N; ++j) {
grid[i][j] += Math.min(grid[i - 1][j], grid[i][j - 1]);
}
}
return grid[M - 1][N - 1];
}
}LeetCode | Minimum Path Sum,布布扣,bubuko.com
原文:http://blog.csdn.net/perfect8886/article/details/21413087