一个基础型模板包括一个向量的实现
DATE: 2015-06-01
#define op operator #define __ while #define _0 return typedef long long ll; inline ll _(ll a,ll b){ll t;__(a){t=a;a=b%a;b=t;}_0 b;} struct frac{ ll u,d; frac(ll u=0,ll d=1):u(u),d(d){} frac op()(){ll _1=_(u,d);_0 frac(u/_1,d/_1);} frac op*(frac b){_0 (frac(u*b.u,d*b.d))();} frac op/(frac b){_0 (frac(u*b.d,d*b.u))();} frac op*(ll n){_0 (frac(u*n,d))();} frac op/(ll n){_0 (frac(u,d*n))();} frac op[](ll n){_0 frac(u*n,d*n);} frac op+(ll n){_0 frac(u+d*n,d);} frac op-(ll n){_0 frac(u-d*n,d);} frac op+(frac b){frac _1=(*this)[b.d],_2=b[d];_0 (frac(_1.u+_2.u,_1.d))();} frac op-(frac b){frac _1=(*this)[b.d],_2=b[d];_0 (frac(_1.u-_2.u,_1.d))();} void op=(ll b){d=1,u=b;} ll op()(frac b){return u*b.d-d*b.u;}//<=> bool op==(frac b){return u==b.u&&d==b.d;} bool op>(frac b){return b(*this)<0;} bool op<(frac b){return b(*this)>0;} }; frac op/(ll a,frac b){_0 (frac(b.d*a,b.u))();} frac op-(ll a,frac b){_0 frac(a)-b;} frac op+(ll a,frac b){_0 frac(a)+b;} frac op*(ll a,frac b){_0 (frac(a*b.u,b.d))();} typedef struct vec{ frac x,y; vec(frac x,frac y):x(x),y(y){}; vec op+(vec b){_0 vec(x+b.x,y+b.y);} vec op-(vec b){_0 vec(x-b.x,y-b.y);} vec op*(frac b){_0 vec(x*b,y*b);} vec op/(frac b){_0 vec(x/b,y/b);} vec op*(ll b){_0 vec(x*b,y*b);} vec op/(ll b){_0 vec(x/b,y/b);} frac op*(vec b){_0 x*b.y-y*b.x;}//cross product frac op[](vec b){_0 x*b.x+y*b.y;}//dot product bool op==(vec b){_0 x==b.x&&y==b.y;}//equality test } point;
本模板风格可能引起不适>_<
其实,用‘[]‘做dot product是因为C++中无法重载‘.‘运算符,而在大多数动态语言(比如javascript)中‘.‘与‘[]‘的作用几乎相等,且在javascript中‘.‘是一个‘[]‘的语法糖.
frac里就直接乱凑剩下的符号了>_<
有错误的话请提出来>_<...
原文:http://www.cnblogs.com/tmzbot/p/4544920.html