Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
快慢两指针。
一个指针每次移动一步,另一个指针每次移动两步。如存在环,必有相遇的时候。
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
bool hasCycle(ListNode *head) {
ListNode *one = head;
ListNode *two = head;
while (two && two->next) {
one = one->next;
two = two->next;
two = two->next;
if (one == two)
return true;
}
return false;
}
};原文:http://blog.csdn.net/elton_xiao/article/details/46332007