[LeetCode] #26 Remove Duplicates from Sorted Array

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example,
Given input array nums = [1,1,2],

Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively. It doesn‘t matter what you leave beyond the new length.

将第i的不重复的元素复制到nums[i]，然后移除后续元素。时间：32ms

代码如下：

class Solution {
public:
    int removeDuplicates(vector<int>& nums) {
        if (nums.empty())
            return 0;
        int count = 1;
        for (size_t i = 1; i < nums.size(); ++i){
            if (nums[i - 1] != nums[i]){
                nums[count] = nums[i];
                count++;
            }
        }
        if (count != nums.size())
            nums.erase(nums.begin() + count);
        return count;
    }
};

[LeetCode] #26 Remove Duplicates from Sorted Array

原文：http://www.cnblogs.com/Scorpio989/p/4550561.html