题目链接:hdu 2954 Simpsons’ Hidden Talents
题目大意:给出两个字符串,找出一个子串,为s1的前缀,s2的后缀, 要求子串最长,并且输出该子串。
解题思路:将s1和s2首尾相连,然后求出next数组的next[n+m]的位置,然后和n、m取最小值即为答案。
#include <stdio.h>
#include <string.h>
#define min(a,b) (a)<(b)?(a):(b)
const int N = 1e5+5;
int n, m, next[N];
char s1[N], s2[N];
void getNext () {
int p = 0;
m = strlen(s1+1);
for (int i = 2; i <= m; i++) {
while (p > 0 && s1[p+1] != s1[i])
p = next[p];
if (s1[p+1] == s1[i])
p++;
next[i] = p;
}
}
int main () {
while (scanf("%s%s", s1+1, s2+1) == 2) {
n = min (strlen(s1+1), strlen(s2+1));
strcat (s1+1, s2+1);
getNext ();
int ans = min (next[m], n);
for (int i = 1; i <= ans; i++) printf("%c", s1[i]);
if (ans) printf(" ");
printf("%d\n", ans);
}
return 0;
}
hdu 2954 Simpsons’ Hidden Talents(KMP),布布扣,bubuko.com
hdu 2954 Simpsons’ Hidden Talents(KMP)
原文:http://blog.csdn.net/keshuai19940722/article/details/21483799