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【Clone Graph】cpp

时间:2015-06-05 11:33:13      阅读:164      评论:0      收藏:0      [点我收藏+]

题目:

Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.


OJ‘s undirected graph serialization:

Nodes are labeled uniquely.

We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.

 

As an example, consider the serialized graph {0,1,2#1,2#2,2}.

The graph has a total of three nodes, and therefore contains three parts as separated by #.

  1. First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
  2. Second node is labeled as 1. Connect node 1 to node 2.
  3. Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle.

 

Visually, the graph looks like the following:

       1
      /      /       0 --- 2
         /          \_/

代码:

/**
 * Definition for undirected graph.
 * struct UndirectedGraphNode {
 *     int label;
 *     vector<UndirectedGraphNode *> neighbors;
 *     UndirectedGraphNode(int x) : label(x) {};
 * };
 */
class Solution {
public:
        UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node)
        {
            map<UndirectedGraphNode *, UndirectedGraphNode *> copied;
            return Solution::dfs(copied, node);
        }
        static UndirectedGraphNode *dfs(
            map<UndirectedGraphNode *, UndirectedGraphNode *>& copied, 
            UndirectedGraphNode *node)
        {
            if ( node == NULL) return NULL;
            if ( copied.find(node)!=copied.end() ) return copied[node];
            UndirectedGraphNode *cloneNode = new UndirectedGraphNode(node->label);
            copied[node] = cloneNode;
            for ( int i=0; i<node->neighbors.size(); ++i )
            {
                cloneNode->neighbors.push_back( Solution::dfs(copied,node->neighbors[i]) );
            }
            return cloneNode;
        }
};

tips:

图的深拷贝。

学到的一个技巧是如何不重复拷贝图中的node:用一个map<node *, node *>记录已经拷贝过的原图中的点以及其对应的新图中的点。

剩下的就是按照深搜模板来完成。

【Clone Graph】cpp

原文:http://www.cnblogs.com/xbf9xbf/p/4554066.html

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