UVa439 - Knight Moves

题目地址：点击打开链接

跟象棋中马一样的走法，BFS遍历

C++代码：

#include <iostream>
#include <string>
#include <cstring>
#include <deque>
#include <utility>
using namespace std;
const int maxsize = 10;
int visited[maxsize][maxsize];
int num[maxsize][maxsize];
int d[8][2]={-1,2,-1,-2,1,2,1,-2,2,-1,2,1,-2,-1,-2,1};
int main()
{
	string a,b;
	while(cin>>a>>b)
	{
		int start_x=a[0]-‘a‘;
		int start_y=a[1]-‘1‘;
		int end_x=b[0]-‘a‘;
		int end_y=b[1]-‘1‘;
		memset(visited,0,sizeof(visited));
		memset(num,0,sizeof(num));
		visited[start_x][start_y]=1;
		deque<pair<int,int> > dp;
		dp.push_back(make_pair(start_x,start_y));
		while(!dp.empty()&&(dp.front().first!=end_x||dp.front().second!=end_y))
		{
			int a=dp.front().first;
			int b=dp.front().second;
			dp.pop_front();
			for(int i=0;i<8;++i)
			{
				int x=a+d[i][0];
				int y=b+d[i][1];
				if(x>=0&&x<8&&y>=0&&y<8&&!visited[x][y])
				{
					visited[x][y]=1;
					num[x][y]=num[a][b]+1;
					dp.push_back(make_pair(x,y));
				}
			}
		}
		cout<<"To get from "<<a<<" to "<<b<<" takes "<<num[end_x][end_y]<<" knight moves."<<endl;
	}
	return 0;
}

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UVa439 - Knight Moves

原文：http://blog.csdn.net/leizh007/article/details/21649377