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222. Count Complete Tree Nodes

时间:2015-06-09 09:45:51      阅读:224      评论:0      收藏:0      [点我收藏+]

Given a complete binary tree, count the number of nodes.

Definition of a complete binary tree from Wikipedia:
In a complete binary tree every level, except possibly the last, is completely filled, and all nodes in the last level are as far left as possible. It can have between 1 and 2h nodes inclusive at the last level h.

解法一:递归,如果左侧高度等于右侧高度,则有2^h - 1个叶子节点。否则递归左右子树找节点个数。

/**
* Definition for a binary tree node.
* public class TreeNode {
*    int val;
*    TreeNode left;
*    TreeNode right;
*    TreeNode(int x) { val = x; }
* }
*/
public class Solution {
  public int countNodes(TreeNode root) {
    if (root == null) {
      return 0;
    }
    int left = 0;
    int right = 0;
    TreeNode tmp = root;
    while(tmp != null) {
      left++;
      tmp = tmp.left;
    }
    tmp = root;
    while(tmp != null) {
      right++;
      tmp = tmp.right;
    }
    if (left == right) {
      return (int)Math.pow(2, left) - 1;
    }
    return 1 + countNodes(root.left) + countNodes(root.right);
  }
}

222. Count Complete Tree Nodes

原文:http://www.cnblogs.com/shini/p/4562534.html

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