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【ZigZag Conversion】cpp

时间:2015-06-09 11:11:41      阅读:218      评论:0      收藏:0      [点我收藏+]

题目:

The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N
A P L S I I G
Y   I   R

And then read line by line: "PAHNAPLSIIGYIR"

 

Write the code that will take a string and make this conversion given a number of rows:

string convert(string text, int nRows);

convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

代码:

class Solution {
public:
    string convert(string s, int numRows) {
            const int len = s.size();
            if ( len<numRows || numRows==1 ) return s;
            vector<char> ret;
            const int INTERVAL = 2*numRows-2;
            for ( int i=0; i<numRows; ++i )
            {
                int interval = 2*(numRows-i)-2;
                for ( int j=i; j<len; interval=INTERVAL-interval)
                {
                    ret.push_back(s[j]);
                    j = (interval==INTERVAL||interval==0) ? j+INTERVAL : j+interval;
                }
            }
            return string(ret.begin(),ret.end());
    }
};

tips:

找到ZigZag每行元素在元字符串s中间隔大小的规律。

【ZigZag Conversion】cpp

原文:http://www.cnblogs.com/xbf9xbf/p/4562639.html

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