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Leetcode[153]-Find Minimum in Rotated Sorted Array

时间:2015-06-11 13:02:36      阅读:157      评论:0      收藏:0      [点我收藏+]

Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

Find the minimum element.

You may assume no duplicate exists in the array.


方法一:直接遍历,暴力求解

class Solution {
public:
    int findMin(vector<int>& nums) {
        int n = nums.size();
        int min = nums[0];
        for(int  i = 1; i < n; i++) {
            if(nums[i]<min){
                min = nums[i];
            }
        }
        return min;
    }
};

Leetcode[153]-Find Minimum in Rotated Sorted Array

原文:http://blog.csdn.net/dream_angel_z/article/details/46454881

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