LeetCode 82: Remove Duplicates from Sorted List II

Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.

For example,
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.

此题要求删除链表中所有重复出现过的元素。代码如下：

ListNode* deleteDuplicates(ListNode* head) {
		ListNode tmpHead(-1);
		ListNode *pTail = &tmpHead;
		ListNode *pNode = head;
		while (pNode)
		{
			ListNode* pNext = pNode->next;
			if (pNext == NULL || pNode->val!=pNext->val)
			{
				pNode->next = pTail->next;
				pTail->next = pNode;
				pTail = pTail->next;
				pNode = pNext;

			}else{
				while (pNext && pNext->val ==pNode->val)
				{
					pNext =pNext->next;
				}
				pNode = pNext;
			}

		}
		return tmpHead.next;

	}

LeetCode 82: Remove Duplicates from Sorted List II

原文：http://blog.csdn.net/sunao2002002/article/details/46506889