Implement the following operations of a stack using queues.
push to back,
peek/pop from front, size, andis empty operations are valid.Update (2015-06-11):
The class name of the Java function had been updated to
MyStack instead of Stack.
[思路]
没想出啥好的办法. 就是两个queues, 轮流把除最后一个之外的都放入另一个queue中.
[CODE]
class MyStack {
// Push element x onto stack.
Queue<Integer> q1 = new LinkedList<Integer>();
Queue<Integer> q2 = new LinkedList<Integer>();
public void push(int x) {
q1.offer(x);
}
// Removes the element on top of the stack.
public void pop() {
while(q1.size()>1) q2.offer(q1.poll());
q1.poll();
Queue<Integer> q = q1;
q1 = q2;
q2 = q;
}
// Get the top element.
public int top() {
while(q1.size()>1) q2.offer(q1.poll());
int x = q1.poll();
q2.offer(x);
Queue<Integer> q = q1;
q1 = q2;
q2 = q;
return x;
}
// Return whether the stack is empty.
public boolean empty() {
return q1.isEmpty();
}
}leetcode 225: Implement Stack using Queues
原文:http://blog.csdn.net/xudli/article/details/46554853