首页 > 编程语言 > 详细

[LeetCode][JavaScript]Best Time to Buy and Sell Stock II

时间:2015-06-20 01:26:00      阅读:243      评论:0      收藏:0      [点我收藏+]

Best Time to Buy and Sell Stock II

Say you have an array for which the ith element is the price of a given stock on day i.

Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).

https://leetcode.com/problems/best-time-to-buy-and-sell-stock-ii/

 

 

 


 

 

 

一图流解释,谷底买,峰顶抛。

技术分享

 1 /**
 2  * @param {number[]} prices
 3  * @return {number}
 4  */
 5 var maxProfit = function(prices) {
 6     var min = Infinity;
 7     var max = -Infinity;
 8     var res = 0;
 9     for(var i = 0; i < prices.length; i++){
10         if(!isFinite(max) && prices[i] < min){
11             min = prices[i];
12         }else if(isFinite(min) && prices[i] >= max){
13             max = prices[i];
14         }else if(isFinite(min) && prices[i] < max){
15             res += max - min;
16             min = prices[i];
17             max = -Infinity;
18         }
19     }
20     if(max > min){
21         res += max - min;
22     }
23     return res;
24 };

 

 

[LeetCode][JavaScript]Best Time to Buy and Sell Stock II

原文:http://www.cnblogs.com/Liok3187/p/4589965.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!