Find the total area covered by two rectilinear rectangles in a 2D plane.
Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.
Assume that the total area is never beyond the maximum possible value of int.
题目大意：给定两个矩形的左下、右上坐标，求出两个矩形一共覆盖的面积。
解题思路：两个矩形面积加起来减去重叠的即可。
public class Solution { public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) { int sq = (C-A)*(D-B)+(G-E)*(H-F); long len = (long)Math.min(C,G)-(long)Math.max(A,E); long we = (long)Math.min(D,H)-(long)Math.max(B,F); if(len<=0||we<=0){ return sq; } return (int)(sq-len*we); } }
原文：http://www.cnblogs.com/aboutblank/p/4599554.html