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Breadth-first

时间:2015-06-27 11:23:24      阅读:164      评论:0      收藏:0      [点我收藏+]

 

Also, listed below is pseudocode for a simple queue based level order traversal, and will require space proportional to the maximum number of nodes at a given depth. This can be as much as the total number of nodes / 2. A more space-efficient approach for this type of traversal can be implemented using an iterative deepening depth-first search.

levelorder(root)
  q = empty queue
  q.enqueue(root)
  while not q.empty do
    node := q.dequeue()
    visit(node)
    if node.left ≠ null then
      q.enqueue(node.left)
    if node.right ≠ null then
      q.enqueue(node.right)

  

Breadth-first

原文:http://www.cnblogs.com/hephec/p/4603721.html

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