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58. Length of Last Word

时间:2015-07-01 12:06:51      阅读:162      评论:0      收藏:0      [点我收藏+]

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

实现题。

public class Solution {
  public int lengthOfLastWord(String s) {
    char[] c = s.toCharArray();
    int count = 0;
    for (int i = c.length - 1; i >= 0; i--) {
      if (c[i] == ‘ ‘ && count > 0) {
        break;
      }
      if (c[i] != ‘ ‘) {
        count++;
      }
    }
    return count;
  }
}

58. Length of Last Word

原文:http://www.cnblogs.com/shini/p/4612700.html

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