用一条SQL语句 查询出每门课程都大于80分的学生姓名" 的实现方式

 1 create table Score(
 2 name varchar(20),
 3 course varchar(20),    
 4 score int)
 5 
 6 go
 7 
 8 insert Score 
 9 select ‘HanMeimei‘,‘Chinese‘,81 union all
10 select ‘HanMeimei‘,‘Mathematics‘,75 union all 
11 select ‘HanMeimei‘,‘History‘,81 union all 
12 select ‘HanMeimei‘,‘Geography‘,75 union all 
13 select ‘LiLei‘,‘Chinese‘,88 union all 
14 select ‘LiLei‘,‘Mathematics‘,90 union all 
15 select ‘JimGreen‘,‘Chinese‘,81 union all 
16 select ‘JimGreen‘,‘Mathematics‘,100 union all 
17 select ‘JimGreen‘,‘English‘,90

1 select distinct name 
2 from score a 
3 where not exists(select 1 from score where a.name=name and score<80)

1 select distinct name 
2 from score 
3 where name not in (select name from score where score<80)

1 select name
2 from score 
3 group by name 
4 having COUNT(1)=SUM(case when score>=80 then 1 else 0 end)

1 select name 
2 from score
3 group by name 
4 having MIN(score)>=80