LeetCode之Path Sum

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

              5
             /             4   8
           /   /           11  13  4
         /  \              7    2      1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool hasPathSum(TreeNode *root, int sum) {
        if (!root) return false;
        if(!root->left&&!root->right&&sum==root->val)
            return true;
		return hasPathSum(root->left, sum - root->val) ||
			   hasPathSum(root->right, sum - root->val);
    }
};

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LeetCode之Path Sum

原文：http://blog.csdn.net/smileteo/article/details/21992275