42.翻转单词顺序VS左旋转字符串

void Reverse(char* pBegin, char* pEnd)
{ 
if (pBegin == NULL || pEnd == NULL)
return;
while (pBegin < pEnd)
{
char temp = *pBegin;
*pBegin = *pEnd;
*pEnd = temp;
pBegin++, pEnd--;
}
}

char* ReverseSentence(char *pData)
{
if (pData == NULL)
return NULL;
char* pBegin = pData;
char* pEnd = pData;
while (*pEnd != ‘\0‘)
pEnd++;
pEnd--;
//翻转整个句子
Reverse(pBegin, pEnd);
//翻转句子中的每个单词
pBegin = pEnd = pData;
while (*pBegin != ‘\0‘)
{
if (*pBegin == ‘ ‘)
{
pBegin++;
pEnd++;
}
else if (*pEnd == ‘ ‘ || *pEnd == ‘\0‘)
{
Reverse(pBegin, --pEnd);
}
else
{
pEnd++;
}
}
return pData;
}

char* LeftRotateString(char* pStr, int n)
{
if (pStr != NULL)
{
int nLength = static_cast<int>(strlen(pStr));
if (nLength > 0 && n > 0 && n < nLength)
{
char* pFirstStart = pStr;
char* pFirstEnd = pStr + n - 1;
char* pSecondStart= pStr + n;
char* pSecondEnd = pStr + nLength - 1;
//翻转字符串的前面n个字符
Reverse(pFirstStart, pFirstEnd);
//翻转字符串的后面部分
Reverse(pSecondStart, pSecondEnd);
//翻转整个字符串
Reverse(pFirstStart, pSecondEnd);
}
}
return pStr;
}

42.翻转单词顺序VS左旋转字符串

原文：http://blog.csdn.net/wangfengfan1/article/details/46835233