Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

//其实题目意思为删除给定的节点

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    void deleteNode(ListNode* node) {
        
        ListNode *next = node->next;  
        node->val = next->val;  
        node->next = next->next; 
    }
};

这样可以吗？不用直接删除当前历元，而是用下一历元的内容来覆盖

Delete Node in a Linked List

原文：http://www.cnblogs.com/jason1990/p/4649271.html