escape(s, t)函数的实现

<span style="font-size:18px;">#include <stdio.h>
#include <stdlib.h>

void escape(char *s, char *t);

int main(void)
{
	char *s = malloc(30);
	char *t = "what is your name?";
	escape(s, t);
	printf("%s\n", t);
	printf("%s\n", s);

	return 0;
}


void escape(char *s, char *t)
{
	int i = 0,len = 0;
	static int j = 0;
	for (i = 0; *(t + i) != '\0'; i++)
	{
		switch (*(t + i))
		{
			case '\n':
				*(s + (j++)) = '\\';
				*(s + (j++)) = 'n';
				break;
			case '\t':
				*(s + (j++)) = '\\';
				*(s + (j++)) = 't';
				break;
			default:
				*(s + (j++)) = *(t + i);
				break;
		}
	}
	*(s + (j)) = '\0';
}


</span>

escape(s, t)函数的实现

原文：http://blog.csdn.net/fly_lhw/article/details/46957633