Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input
Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.
Output
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input
-1000000 9
Sample Output
-999,991
将a+b的和从低到高,三位的隔开.
在这里我们直接使用stack来存储,需要注意res=0的情况;输出第一个和剩下来的补全问题
#include <bits/stdc++.h> #define LL long long #define MAXN 100000+50 #define MOD 1000000007 using namespace std; stack<int> s; int main(){ int res, a, b; scanf("%d%d", &a, &b); res = a+b; if(!res){ printf("0"); return 0; } if(res < 0){ printf("-"); res = -res; } while(res){ s.push(res%1000); res /= 1000; } bool flag = false; while(!s.empty()){ if(!flag){ printf("%d", s.top()); s.pop(); flag = true; } else{ printf(",%03d", s.top()); s.pop(); } } return 0; }
原文：http://www.cnblogs.com/capouis/p/4662616.html
