leetcode-205-Isomorphic Strings

                                        Isomorphic Strings

Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given "egg", "add", return true.

Given "foo", "bar", return false.

Given "paper", "title", return true.

Note:
You may assume both s and t have the same length.

两字符串有映射关系，即一一对应关系。

如egg,add.

e和a对应，g和d对应

刚开始用的map

class Solution {
public:
    bool isIsomorphic(string s, string t) {
        int n =s.length();
        map<int,int>m1,m2;
        for (int i = 0;i < n;i++) {
            m1[s[i]] = t[i];
            m2[t[i]] = s[i];
        }
        for (int i = 0;i < n;i++) {
            if (m1[s[i]] != t[i]) return false; 
            if (m2[t[i]] != s[i]) return false;
        }
        return true;
    }
};

class Solution {
public:
    bool isIsomorphic(string s, string t) {
        int n =s.length();
        int m1[130] = {0},m2[130] = {0};
        for (int i = 0;i < n;i++) {
            m1[s[i]] = t[i];
            m2[t[i]] = s[i];
        }
        for (int i = 0;i < n;i++) {
            if (m1[s[i]] != t[i]) return false; 
            if (m2[t[i]] != s[i]) return false;
        }
        return true;
    }
};

leetcode-205-Isomorphic Strings

原文：http://blog.csdn.net/u014705854/article/details/47070527