首页 > 其他 > 详细

[leedcode 141] Linked List Cycle

时间:2015-07-26 22:33:35      阅读:262      评论:0      收藏:0      [点我收藏+]

Given a linked list, determine if it has a cycle in it.

Follow up:
Can you solve it without using extra space?

/**
 * Definition for singly-linked list.
 * class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) {
 *         val = x;
 *         next = null;
 *     }
 * }
 */
public class Solution {
    public boolean hasCycle(ListNode head) {
        //双指针,一快一慢,绝对速度为1,如果相遇 有环,马上返回,fast==null或者fast为尾节点时,返回false
        if(head==null) return false;
        ListNode fast=head;
        ListNode slow=head;
        while(fast!=null&&fast.next!=null){
            fast=fast.next.next;
            slow=slow.next;
            if(fast==slow) return true;
        }
        return false;
    }
}

 

[leedcode 141] Linked List Cycle

原文:http://www.cnblogs.com/qiaomu/p/4678816.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!