C++ 获取类成员函数地址方法 浅析

void print ()
{
   printf ("function print");
}
typdef void (*fun)();
fun f = print;
f();

class test
{
public:
void print ()
{
   printf ("function print");
}
};

typedef void (test::*fun)();
fun f = &test::print;
test t;
(t.*f)();

unsigned int a = reinterpret_cast<unsigned int>(f);//编译错误

http://bbs.pediy.com/showthread.php?t=47835

这里给出了答案.

char buf [32] = {0};
sprintf(buf , "%u", f);
int a = atoi( buf);

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