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LeetCode | Remove Duplicates from Sorted Array II

时间:2014-04-04 16:32:55      阅读:433      评论:0      收藏:0      [点我收藏+]

题目

Follow up for "Remove Duplicates":
What if duplicates are allowed at most twice?

For example,
Given sorted array A = [1,1,1,2,2,3],

Your function should return length = 5, and A is now [1,1,2,2,3].

分析

Remove Duplicates from Sorted Array基础上加上重复计数即可。

代码

public class RemoveDuplicatesFromSortedArrayII {
	public int removeDuplicates(int[] A) {
		if (A == null || A.length == 0) {
			return 0;
		}
		int len = 1;
		int count = 0;
		for (int i = 1; i < A.length; ++i) {
			if (A[i] != A[len - 1]) {
				A[len++] = A[i];
				count = 0;
			} else if (count < 1) {
				++count;
				A[len++] = A[i];
			}
		}
		return len;
	}
}

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LeetCode | Remove Duplicates from Sorted Array II

原文:http://blog.csdn.net/perfect8886/article/details/22919367

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